2y^2+12=7

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Solution for 2y^2+12=7 equation: 



2y^2+12=7

We move all terms to the left:

2y^2+12-(7)=0

We add all the numbers together, and all the variables

2y^2+5=0

a = 2; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·2·5
Δ = -40
Delta is less than zero, so there is no solution for the equation

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